SRM 299 Div II Level Two: Projections

题目来源:http://community.topcoder.com/stat?c=problem_statement&pm=6041

主要是判断什么情况下会占用最小和最大的格子, 其实自己画个图很容易就找的出来.

代码如下:

#include <algorithm>
#include <string>
#include <vector>


using namespace std;

/************** Program  Begin *********************/

class Projections {
public:
    vector <int> count(string front, string right) {
	vector <int> res;
	int mingrid;
	int maxgrid;
	int size = front.size();
	int colsize = 0;
	for (int i = 0; i < size; i++) {
		if ('x' == front[i]) {
			++colsize;
		}
	}
	int rowsize = 0;
	for (int i = 0; i < right.size(); i++) {
		if ('x' == right[i]) {
			++rowsize;
		}
	}
	maxgrid = colsize * rowsize;
	mingrid = max(colsize, rowsize);
	res.push_back(mingrid);
	res.push_back(maxgrid);

	return res;
    }

};

/************** Program End ************************/