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初试JQuery_Ajax

AjaxjQueryServletJavaEEJSP 
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最近闲来无事弄了一下jquery。顺便练习一下基本语句，并尝试着用用封装好的ajax特性

以下是简单知识点的总结：


<%@ page language="java"  pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
	<meta http-equiv="pragma" content="no-cache">
	<meta http-equiv="cache-control" content="no-cache">
	<meta http-equiv="expires" content="0">    
	<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
	<meta http-equiv="description" content="This is my page">
	<script type="text/javascript" src="js/jquery_1.4_All.js"></script>
	<script type="text/javascript">
	function doRequest1(){
		$.ajax({
			type:"post",
			url:"loginServlet",
			data:"username="+$("#username").val()+"&password="+$("#password").val(),
			success:function(msg){
				$("#msg").text(msg);
				$("#msg").val(msg);
			}
		});
	};
		
	</script>
  </head>
  
  <body>
  	<div>
    	<form action="#">
			用户: <input type="text" name="username" id="username"/>
			密码: <input type="text" name="password" id="password"/>
				 <input type="button" id="send" value="提交" onclick="doRequest1();"/>	
		<span id="msg"></span>
		</form>
	</div>
  </body>
</html>

 

package beyondx.ajax;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class LoginServlet extends HttpServlet{

	public void doPost(HttpServletRequest request,HttpServletResponse response)
	throws ServletException,IOException{
		request.setCharacterEncoding("utf-8");
		response.setCharacterEncoding("utf-8");
		String username = request.getParameter("username");
		String password = request.getParameter("password");
		PrintWriter out = response.getWriter();
		if(username.equals("zzz")&&password.equals("111")){
			out.print("welcome "+username);
		}
		else out.print("账号密码错误");
	}
}
 

 <?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.5" 
	xmlns="http://java.sun.com/xml/ns/javaee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
	http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
  	<servlet-name>loginServlet</servlet-name>
  	<servlet-class>beyondx.ajax.LoginServlet</servlet-class>
  </servlet>
  <servlet-mapping>
  	<servlet-name>loginServlet</servlet-name>
  	<url-pattern>/loginServlet</url-pattern>
  </servlet-mapping>
</web-app>
 

希望对想了解jquery的朋友有所帮助。


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