synchronized测试

1、现有一个简单类UserVo，有两个打印方法。

package main.java.com.ji.test;

public class UserVo {

	private String name;
	private int age;
	
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public int getAge() {
		return age;
	}
	public void setAge(int age) {
		this.age = age;
	}
	
	public synchronized void printName() {
		System.out.println("name ....in  ....");
		try {
			Thread.sleep(1000);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		System.out.println("name .... = ");
	}

	
	public synchronized void printAge() {
		System.out.println("age .... in  ....");
		try {
			Thread.sleep(1000);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		System.out.println("age .... = ");
	}
}

 另写了一个测试类

 

 

package main.java.com.ji.test;

public class MyThread implements Runnable {

	private UserVo userVo;
	
	public MyThread(UserVo userVo) {
		this.userVo = userVo;
	}
	@Override
	public void run() {
		userVo.printName();
	}

	
	
	public static void main(String[] args) {
		UserVo userVo = new UserVo();
		userVo.setAge(99);
		userVo.setName("admin....xxx");

		UserVo userVo2 = new UserVo();
		userVo2.setAge(99222);
		userVo2.setName("222admin....xxx");
		for (int i = 0; i < 10; i++) {
			new Thread(new MyThread(userVo)).start();
			new Thread(new MyThreadAge(userVo)).start();
		}
	}
}

class MyThreadAge implements Runnable {

	private UserVo userVo;
	
	public MyThreadAge(UserVo userVo) {
		this.userVo = userVo;
	}
	@Override
	public void run() {
		userVo.printAge();
	}
}

 

 

2、如果想执行

for (int i = 0; i < 10; i++) {
			new Thread(new MyThread(userVo)).start();
			new Thread(new MyThreadAge(userVo)).start();
		}

 循环的时候，每个单独的printName和printAge不被打断的话，两个方法前需加关键字synchronized

 

3、、如果想执行

for (int i = 0; i < 10; i++) {
			new Thread(new MyThread(userVo)).start();
			new Thread(new MyThreadAge(userVo2)).start();
		}

 循环的时候，每个单独的printName和printAge不被打断的话，两个方法前需加关键字 static synchronized

 

评论

1 楼 bozch 2017-09-22  

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