jsp 用urlrewrite 实现URL 重写

是否看到别人的网站网址名都不带后缀名比较酷，比如qq空间的地址，其实用urlrewrite这个包很容易就实现了。
    下面是使用说明：

1.下载urlrewrite,官方下载地址：http://tuckey.org/urlrewrite/dist/urlrewritefilter-2.6.zip

2.解压缩文件，压缩包内文件copy到项目中(压缩包位置 -> 项目位置)：

urlrewrite-2.6.0-src/webapp/WEB-INF/lib/urlrewrite-2.6.0.jar -> WebRoot/WEB-INF/lib/urlrewrite-2.6.0.jar

urlrewrite-2.6.0-src/webapp/WEB-INF/urlrewrite.xml -> WebRoot/WEB-INF/urlrewrite.xml
3.将以下代码添加到web.xml里

<filter>
        <filter-name>UrlRewriteFilter</filter-name>
        <filter-class>
            org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
        </filter-class>
    </filter>
    <filter-mapping>
        <filter-name>UrlRewriteFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

 

4.修改urlrewrite.xml

<?xml version="1.0" encoding="utf-8"?> 
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN" 
"http://tuckey.org/res/dtds/urlrewrite2.6.dtd"> 

<!-- 

Configuration file for UrlRewriteFilter 
http://tuckey.org/urlrewrite/ 

--> 
<urlrewrite> 
	<rule> 
		<from>^/([a-z]+)$</from> 
		<to type= "forward" >/world.jsp?id=$1</to> 
	</rule> 
	<rule>
	    <from>^/world/(.*)$</from>
	    <to>/world.jsp?tid=$1</to>
	</rule>
	<rule>
		<from>^/(.*).html$</from>
		<to>/test1/$1.jsp</to>
	</rule>
	
	<outbound-rule> 
		<note> 
		The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url) 
		the url /rewrite-status will be rewritten to /test/status/. 
		
		The above rule and this outbound-rule means that end users should never see the 
		url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks 
		in your pages. 
		</note> 
		<from>/rewrite-status</from> 
		<to>/test/status/</to> 
	</outbound-rule>
</urlrewrite> 

 rule是url重写规则,from是显示出来的地址,to是映射的实际地址,$1是重写参数,可以为多个,()里是匹配的正则表达式.
好了,在项目中新建world.jsp,启动tomcat,输入
http://localhost:8080/mysite/world/1

mysite是你的项目名

实际上访问的是http://localhost:8080/mysite/world.jsp?tid=1
这样就简单的实现了伪静态的效果