新博文地址:[leetcode]Remove Duplicates from Sorted Array II
Remove Duplicates from Sorted Array II
Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?
For example,
Given sorted array A = [1,1,1,2,2,3],
Your function should return length = 5, and A is now [1,1,2,2,3].
What if duplicates are allowed at most twice?
For example,
Given sorted array A = [1,1,1,2,2,3],
Your function should return length = 5, and A is now [1,1,2,2,3].
具有又是漏网之鱼,算了,第一遍写的太烂,大家直接戳新博文,或者往下看,反正都是从新博文copy过来的算法:
public class Solution { public int removeDuplicates(int[] A) { if(A == null || A.length == 0) return 0; int index = 1; boolean twice = false; for(int i = 1; i < A.length; i++){ if(A[i] == A[i - 1] ){ if(!twice){ twice = true; A[index++] = A[i]; } }else{ twice = false; A[index++] = A[i]; } } return index; } }
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