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Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
计算一个整数中1的个数。通过位运算,每次右移一位,判断是否为1,如果为1计数器加1,代码如下:
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
计算一个整数中1的个数。通过位运算,每次右移一位,判断是否为1,如果为1计数器加1,代码如下:
public class Solution { // you need to treat n as an unsigned value public int hammingWeight(int n) { int count = 0; for(int i = 0; i < 32; i++) { count += (n >> i & 1); } return count; } }
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