java字符统计

    之前看到几个迅雷的上机题,于是在空闲之余写了一个简单的测试:(代码测试通过,如果需要应用到时间项目中需要对异常处理进行处理,也仅代表个人观点,仅供参考,欢迎大家提出更优解决方案)

// 统计文件中指定字符出现个数和位置以及在文件中的行数
BufferedReader in = null;
		int count = 0;
		int line = 0;
		try{
			File f = new File("E:\\ftp.txt");
			in = new BufferedReader(new InputStreamReader(new FileInputStream(f)));
			String readLine = null;
			String searchStr = "java";
			while((readLine = in.readLine()) != null){
				++ line;
				int position = readLine.indexOf(searchStr);
				if(position != -1){
					++ count;
					System.out.println(readLine + "\t\t文件第 " + line  + "行\t\t偏移量：" + position);
				}
			}
			System.out.println("\n字符串出现次数：" +  count);
		}catch(FileNotFoundException e){
			
		}catch(IOException ex){
			
		}finally{
			try{
				if(in != null)
					in.close();
			}catch(Exception exx){}
		}


// 统计文件中的字符、数字、空格、以及其它字符
int digit = 0;
int whiteSpace = 0;
int letter = 0;
int another = 0;
BufferedReader in = null;
		try{
			// DataInputStream in = new DataInputStream(new FileInputStream(new File("E:\\ftp.txt")));
			in = new BufferedReader(new InputStreamReader(new FileInputStream(new File("E:\\ftp.txt"))));
			String readLine = null;
			while((readLine = in.readLine()) != null){
				// Character ch = new Character(c);
				char c ;
				for(int i=0;i<readLine.length();i++){
					c = readLine.charAt(i);
					if(Character.isDigit(c))
						++ digit;
					else if(Character.isLetter(c))
						++ letter;
					else if(Character.isWhitespace(c))
						++ whiteSpace;
					else
						++ another;
				}
			}
			System.out.println("数字个数：" + digit + "\n字符个数：" + letter + "\n空格个数：" + whiteSpace + "\n其它字符：" + another);
		}catch(FileNotFoundException ex){
			System.out.println("ex:" +ex.getMessage());
		}catch(IOException e){
			System.out.println("e:" + e.getMessage());
		}finally{
			try{
				if(in != null)
					in.close();
			}catch(Exception exx){}
		}