Reverse an array

	private  void reverse(Object[] anArray){
		if (anArray == null){
			return;
		}
		reverseArgrithmTwo(anArray);
	}
	
//	private void reverseArgrithmOne(Object[] anArray){
//		int maxIndex = anArray.length - 1;
//		for (int index=(maxIndex-1)>>1;index>=0;index--) {		
//			Object temp = anArray[index];
//			anArray[index] = anArray[maxIndex - index];
//			anArray[maxIndex-index] = temp;
//		}
//	}
	
	private  void reverseArgrithmTwo(Object[] anArray){
		for (int index = 0; index<anArray.length/2;index++)
		{
			Object temp = anArray[index];
			anArray[index]= anArray[anArray.length-1-index];
			anArray[anArray.length-1-index] = temp; 
		}
	}

 

 

The test cases go below:

	@Test
	public void reverseAnArray(){
		Integer[] original = {3,5,1,-2,0};
		reverse(original);
		assertArrayEquals(new Integer[]{0,-2,1,5,3}, original);
	}
	
	@Test
	public void reverseAnOnlyOneElementArray(){
		Integer[] oneElementArray = {5};
		reverse(oneElementArray);
		assertArrayEquals(new Integer[]{5}, oneElementArray);
	}
	
	@Test public void reverseArrayHasZeroElement(){
		Integer[] zeroElementArray = new Integer[0];
		reverse(zeroElementArray);
		assertArrayEquals(new Integer[0], zeroElementArray);
	}
	
	@Test
	public void reverseNullArray(){
		Integer[] nullArray = null;
		reverse(nullArray);
		assertNull(nullArray);
	}