Given a collection of integers that might contain duplicates, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,2]
, a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
class Solution { public: vector<vector<int> > subsetsWithDup(vector<int> &S) { vector<vector<int> > ret; if(S.size() == 0) return ret; sort(S.begin(), S.end()); vector<int> tmp; dfs(S, 0, tmp, ret); return ret; } void dfs(vector<int> &S, int beg, vector<int> tmp, vector<vector<int> > &ret) { ret.push_back(tmp); if(beg >= S.size()) return; for(int i = beg; i < S.size(); ++i) { if(i == beg || S[i] != S[i-1]) { tmp.push_back(S[i]); dfs(S, i+1, tmp, ret); tmp.pop_back(); } } } };
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