enctype="multipart/form-data"中Form参数的获取

enctype="multipart/form-data"中Form参数的获取

博客分类：
• Web

Apache 

如果表单使用enctype="multipart/form-data"方式提交，
那么一般的request.getParameter(arg0)方法是无法获取Form参数的，
思考ing，
发现使用apache的common-fileupload组件可以获取，

 

DiskFileUpload upload = new DiskFileUpload();
upload.setHeaderEncoding("UTF-8");
try {
    List items = upload.parseRequest(request);
    Iterator iter = items.iterator();
    while (iter.hasNext()) {
        FileItem item = (FileItem) iter.next();
        if (item.isFormField()) {
          //参数名
          item.getFieldName();
          //参数值
          item.getString("UTF-8");
        }
    }
}catch (Exception ex) {
}

 String fieldValue = "";
      DiskFileUpload uploadParm = new DiskFileUpload();                            
      uploadParm.setHeaderEncoding("UTF-8");                             
      try {                             
          List items = uploadParm.parseRequest(request);                            
          Iterator iterator = items.iterator();                            
          while (iterator.hasNext()) {                             
              FileItem fileItem = (FileItem) iterator.next();                            
              if (fileItem.isFormField()) {                             
                //参数名                             
               if("fileRowId".equals(fileItem.getFieldName())){                            
                //参数值                             
                fieldValue = fileItem.getString("UTF-8"); 
                break;
               }
              }                            
          }                            
       }catch (Exception ex) {                             
      }     

  

 

 

注意，如果不能使用item.getString()，然后自行转换编码，

这样会出现乱码的，

new String(item.getString().getBytes(),"UTF-8")

这样会出现乱码

试了很多方法，这是目前发现唯一能解决乱码问题的方法