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Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
1 自己的代码
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
1 自己的代码
package leetcode; import java.util.Arrays; public class SingleNumberII { public int singleNumber(int[] A) { Arrays.sort(A); int index = 0; for(int i = 0; i < A.length; i = i + 3){ if(i == A.length-1) index = i;//处理数组中只有一个、处理singleNumber在数组最后的情况 else{ if(A[i] == A[i+1]) continue; else {index = i; break;} } } return A[index]; } }
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