先申明,我是自己琢磨出来的,不知道对不对!!
但是,我想应该不会有太大的出入的!
getRequestURI()就相当于你在写一个JSP页面的时候会有这样的东西"action='/WebRoot/xxx'"这个方法就是获得'/WebRoot/xxx',也就是说它会得到一个相对地址
而getRequestURL()会得到一个完整的URL地址,也就是绝对的绝对地址
Request.getRequestURL返回的是请求的全部，包括Http协议，端口号，servlet名字和映射路径，但它不包含请求参数。
request.getRequestURI得到的是request URL的部分值，并且web容器没有decode过的
Java code
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-->getRequestURL：
public java.lang.StringBuffer getRequestURL()
Reconstructs the URL the client used to make the request. The returned URL contains a protocol, server name, port number, and server path, but it does not include query string parameters.
Because this method returns a StringBuffer, not a string, you can modify the URL easily, for example, to append query parameters.
This method is useful for creating redirect messages and for reporting errors.
Returns:
a StringBuffer object containing the reconstructed URL
getRequestURI：
public java.lang.String getRequestURI()
Returns the part of this request's URL from the protocol name up to the query string in the first line of the HTTP request. The web container does not decode this String. For example:
First line of HTTP request Returned Value
POST /some/path.html HTTP/1.1 /some/path.html
GET http://foo.bar/a.html HTTP/1.0 /a.html
HEAD /xyz?a=b HTTP/1.1 /xyz
To reconstruct an URL with a scheme and host, use HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest).
Returns:
a String containing the part of the URL from the protocol name up to the query string
See Also:
HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest)
request.getRequestURI() /jqueryWeb/resources/request.jsp
request.getRequestURL() http://localhost:8080/jqueryWeb/resources/request.jsp
request.getContextPath()/jqueryWeb
request.getServletPath()/resources/request.jsp
注： resources为WebContext下的目录名
jqueryWeb 为工程名
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