/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode *root, int sum) {
if(!root) return false;
if(root->val == sum && !root->left && !root->right) return true;
bool lf = hasPathSum(root->left, sum-root->val);
bool rf = hasPathSum(root->right, sum-root->val);
return lf||rf;
}
};
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