Parkside's Triangle
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 3839 | Accepted: 2301 |
Description
Bessie
taught the cows to make Parkside's Triangle. It is generated from two
numbers: the size and the seed. The size N (1 <= N <= 20)
determines how many rows are in the triangle and the seed S (1 <= S
<= 9) determines the first number in the triangle. Here are two
examples:
Analyze the above examples, discover the rule, and write a program that will generate Parkside's Triangle given any size N (1 <= N <= 20) and any seed S (1 <= S <= 9).
N=5, S=3 N=6, S=1 3 4 6 9 4 1 2 4 7 2 7 5 7 1 5 3 5 8 3 8 8 2 6 6 9 4 9 3 7 1 5 1 8 6 2 3The first line of any triangle has no blanks at its front.
Analyze the above examples, discover the rule, and write a program that will generate Parkside's Triangle given any size N (1 <= N <= 20) and any seed S (1 <= S <= 9).
Input
Line 1: Two space-separated integers: N and S
Output
Lines 1..N: Parkside's Triangle as above; no trailing blanks on any line.
Sample Input
5 3
Sample Output
3 4 6 9 4 5 7 1 5 8 2 6 3 7 8
水题++
import java.util.*; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); String[] str = cin.nextLine().split(" "); int N = Integer.valueOf(str[0]).intValue(); int S = Integer.valueOf(str[1]).intValue(); int[][] Tri = new int[N][N]; for(int j = 0; j < N; j++) { for(int i = 0; i <= j; i++) { Tri[i][j] = S; if(S == 9) S = 1; else S++; } } print(Tri); } private static void print(int[][] tri) { for(int i = 0; i < tri.length; i++) { for( int j = 0; j < tri.length - 1; j++) { if(tri[i][j] < 1 || tri[i][j] > 9) System.out.print(" "); else System.out.print(tri[i][j]); System.out.print(" "); } System.out.println(tri[i][tri.length -1]); } } }
发表评论
-
POJ ACM习题【No.2328】
2009-07-05 19:43 895Guessing Game Time ... -
POJ ACM习题【No.3157】
2009-04-26 23:54 1633Java vs C++ Time Lim ... -
POJ ACM习题【No.2924】
2009-04-26 11:52 919Gauß in Elementary School ... -
POJ ACM习题【No.3176】
2009-04-26 10:53 1042Cow Bowling Time Lim ... -
POJ ACM习题【No.2845】
2009-04-25 22:25 120801000001 Time Limit: ... -
POJ ACM习题【No.2140】
2009-04-25 21:26 932Herd Sums Time Limit ... -
POJ ACM习题【No.1969】
2009-04-25 20:59 857Count on Canton Time ... -
POJ ACM习题【No.2840】
2009-04-25 19:24 1002Big Clock Time Limit ... -
POJ ACM习题【No.2521】
2009-04-24 22:41 846How much did the businessman l ... -
POJ ACM习题【No.1326】
2009-04-24 22:14 1007Mileage Bank Time Li ... -
POJ ACM习题【No.3325】
2009-04-24 21:15 1087ICPC Score Totalizer Software ... -
POJ ACM习题【No.2756】
2009-04-24 20:28 770Autumn is a Genius T ... -
POJ ACM习题【No.3062】
2009-04-24 20:10 804Celebrity jeopardy ... -
POJ ACM习题【No.1547】
2009-04-23 20:03 770Clay Bully Time Limi ... -
POJ ACM习题【No.1552】
2009-04-23 19:39 747Doubles Time Limit: ... -
POJ ACM习题【No.1007】
2009-04-23 19:24 845DNA Sorting Time Lim ... -
POJ ACM习题【No.1565】
2009-04-22 22:40 839Skew Binary Time Lim ... -
POJ ACM习题【No.2403】
2009-04-22 22:18 857Hay Points Time Limi ... -
POJ ACM习题【No.1862】
2009-04-22 20:12 694Stripies Time Limit: ... -
POJ ACM习题【No.3224】
2009-04-22 19:57 740Lab杯 Time Limit: 1 ...
相关推荐
方便大家有针对性地联系 祝大家AC愉快~
pojACM题目分类,便于各类型同学分别做题有所参考
相信大家在做poj上的题目的时候如果没有分类的话很迷茫吧....这里有一份目前比较全面的poj题目分类..
02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ题库使用指南.docx02.北大POJ...
acm数据结构总结.doc acm数据结构总结.doc
poj acm题解,包括绝大部分poj题目的题解,可以供acm爱好者学习研究
本文件是ACM里的一些题目的源码、原题和习题的分析及详细解答。欢迎各位下载
http://acm.pku.edu.cn/JudgeOnline/ acm的AC解题报告
POJ ACM 1015 Jury Compromise 两种解法 解题报告
西工大C语言POJ习题答案.docx
PKU 、POJ ACM/ICPC300多题的代码,还有各种典型问题的分类代码
poj 2007 Scrambled Polygon.md
poj 3183 Stump Removal.md
poj 2430 Lazy Cows.md
poj 2900 Griddy Hobby.md
poj 3435 Sudoku Checker.md
poj 1984 Navigation Nightmare.md
poj 2174 Decoding Task.md
poj 2386 Lake Counting.md
poj 3585 Accumulation Degree.md